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\begin{document}

\Large
\noindent \textbf{Problem Set 1} \\
\normalsize
ME 444: Continuum Mechanics \\
D.~H.\ Kelley \\
\numpoints~points \\

\begin{questions}

    \question[2] Show that if the vectors $\bm{a}$, $\bm{b}$, and $\bm{c}$ are linearly dependent, then $\bm{a} \cdot ( \bm{b} \times \bm{c} ) = 0$.

    \question Given 
        \[ \left[ S_{ij} \right] = \left[ 
        \begin{array}{ccc}
            1 & 0 & 2 \\
            0 & 1 & 2 \\
            3 & 0 & 3
        \end{array} \right], \] 
        evaluate the following: 
        \begin{parts}
            \part[1] $S_{ii}$
            \part[1] $S_{ij} S_{ij}$
            \part[1] $S_{jk} S_{jk}$
            \part[1] $S_{mn} S_{nm}$
        \end{parts}
        
    \question Given
        \[ \left[ a_i \right] = \left[ 
        \begin{array}{c} 
            1 \\ 
            0 \\ 
            2 
        \end{array} \right], \,
        \left[ B_{ij} \right] = \left[ 
        \begin{array}{ccc} 
            2 & 3 & 0 \\ 
            0 & 5 & 1 \\ 
            0 & 2 & 1 
        \end{array} \right], \,
        \left[ C_{ij} \right] = \left[ 
        \begin{array}{ccc} 
            0 & 3 & 1 \\ 
            1 & 0 & 2 \\ 
            2 & 4 & 3 
        \end{array} \right], \]
        demonstrate the equivalence of the following subscripted equations and the corresponding matrix equations. In each, indices $i$ and $j$ retain their meanings as defined above (indicating the row and column, respectively, in the \emph{original} quantities $a_i$, $B_{ij}$, and $C_{ij}$); no indices are renamed. 
        \begin{parts}
            \part[1] $ D_{ji} = B_{ij} \Leftrightarrow \bm{D} = \bm{B}^T $
            \part[1] $ b_i = B_{ij} a_j \Leftrightarrow \bm{b} = \bm{B} \bm{a} $ 
            \part[1] $ c_j = B_{ji} a_i \Leftrightarrow \bm{c} = \bm{B}^T \bm{a} $  
            \part[1] $ s = B_{ij} a_i a_j \Leftrightarrow s = \bm{a}^T \bm{B} \bm{a} $ 
        \end{parts}

    \question Given
        \[ [ a_i ] = \left[ 
        \begin{array}{c}
            1 \\
            2 \\
            0 
        \end{array} \right], \,
        [ b_i ] = \left[ 
        \begin{array}{c} 
            0 \\
            2 \\
            3
        \end{array} \right], \,
        [ S_{ij} ] = \left[ 
        \begin{array}{ccc} 
            0 & 1 & 2 \\ 
            1 & 2 & 3 \\ 
            4 & 0 & 1 
        \end{array} \right], \]
        calculate
        \begin{parts}
            \part[2] $ \epsilon_{ijk} a_k $ 
            \part[2] $ \epsilon_{ijk} S_{jk} $ 
            \part[2] $ \epsilon_{ijk} a_i b_j $ 
        \end{parts}

    \question[2] \label{prob:epsdelta} Verify that $ \epsilon_{ijm} \epsilon_{klm} = \delta_{ik} \delta_{jl} - \delta_{il} \delta_{jk}$. 

    \question Calculate and simplify
        \begin{parts}
            \part[1] $ \epsilon_{ilm} \epsilon_{jlm}$ 
            \part[1] $ \epsilon_{ijk} \epsilon_{ijk}$ 
        \end{parts}

    \question[3] Using the result of the problem~\ref{prob:epsdelta}, show that $ \bm{a} \times ( \bm{b} \times \bm{c} ) = ( \bm{a} \cdot \bm{c} ) \bm{b} - ( \bm{a} \cdot \bm{b} ) \bm{c} $. 

    \question[3] Find the components of the tensor $ \bm{T} $ that transforms any vector $ \bm{a} $ into a vector $ \bm{b} = ( \bm{a} \cdot \hat{\bm{n}} ) \hat{\bm{m}} $, where $ \hat{\bm{m}} = (\hat{\bm{e}}_1 + \hat{\bm{e}}_2)/\sqrt{2} $ and $ \hat{\bm{n}} = (\hat{\bm{e}}_1 - \hat{\bm{e}}_3)/\sqrt(2) $. Write the tensor $ \bm{T} $ as a dyadic product. 

    \question[3] Determine the components of the tensor $ \bm{D} $ that transforms any vector $ \bm{a} $ into a vector $ \bm{b} = \bm{a} + \bm{a} \times \bm{g} $, where $ \bm{g} = ( \hat{\bm{e}}_1 + \hat{\bm{e}}_2 - \hat{\bm{e}}_3 )/\sqrt{3} $. 

    \question[4] With respect to the Cartesian basis $ \{ \hat{\bm{e}}_1, \, \hat{\bm{e}}_2, \, \hat{\bm{e}}_3 \} $, the tensor $ \bm{T} $ has components
        \[ [ T_{ij} ] = \left[
        \begin{array}{ccc}
            1 & 2 & -2 \\
            2 & 0 & 0 \\
            -3 & 0 & 1
        \end{array} \right], \]
        and the vector $ \bm{v} $ has components $ \bm{v} = \hat{\bm{e}}_1 + \hat{\bm{e}}_2 -3 \hat{\bm{e}}_3 $. Find the components of $ \bm{T} $ and $ \bm{v} $ with respect to a Cartesian basis $ \{ \hat{\bm{e}}_{1^\prime}, \, \hat{\bm{e}}_{2^\prime}, \, \hat{\bm{e}}_{3^\prime} \} $, where $ \hat{\bm{e}}_{1^\prime} $ is in the direction of $ \hat{\bm{e}}_2 - 2 \hat{\bm{e}}_3 $ and $ \hat{\bm{e}}_{2^\prime} = \hat{\bm{e}}_1 $. 

    \question Given the tensor $ \bm{T} $ with components 
        \[ [ T_{ij} ] = \left[ 
        \begin{array}{ccc}
            1 & 2 & 3 \\
            4 & 5 & 6 \\
            7 & 8 & 9
        \end{array} \right], \]
        \begin{parts}
            \part[2] Find the symmetric and antisymmetric parts of $\bm{T}$. 
            \part[2] Find the dual vector of the antisymmetric part of $\bm{T}$. 
        \end{parts}

    \question[2] Rank-2 tensors $\bm{T}$, $\bm{R}$, and $\bm{S}$ are related by $\bm{T} = \bm{R} \bm{S}$. Tensors $\bm{R}$ and $\bm{S}$ have the same nonzero eigenvector $\bm{n}$ and corresponding eigenvalues $r_1$ and $s_1$. Find an eigenvalue and nonzero eigenvector of $\bm{T}$. 

    \question Consider the dyadic product $\bm{a} \otimes \bm{b}$.
        \begin{parts}
            \part[1] For this dyad, find one nonzero eigenvector that has a nonzero eigenvalue. 
            \part[1] Calculate the first principal scalar invariant of $\bm{a} \otimes \bm{b}$. 
            \part[2] Calculate the third principal scalar invariant of $\bm{a} \otimes \bm{b}$. 
        \end{parts}

    \question[4] A tensor $\bm{T}$ has a matrix representation 
        \[ \left[ T_{ij} \right] = \left[
        \begin{array}{ccc}
            1 & 1 & 0 \\
            1 & 1 & 0 \\
            0 & 0 & 2
        \end{array} \right]. \]
        Find the eigenvalues and three mutually orthogonal, unit-length eigenvectors. 

    \question[3] If $\bm{B}$ is antisymmetric and $\bm{A}$ is symmetric, calculate and simplify $A_{ij} B_{ij}$. 

    \question[2] What topic on this problem set was easy? What topic was hard? What topic was impossible? 

\end{questions}
\end{document}

